73. Set Matrix Zeroes

1. Description

Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0’s.
You must do it in place.

2. Example

Example 1

Example 1
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]]
Output: [[1,0,1],[0,0,0],[1,0,1]]

Example 2

Leetcode 73
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]

3. Constraints

  • m == matrix.length
  • n == matrix[0].length
  • 1 <= m, n <= 200
  • -2$^{31}$ <= matrix[i][j] <= 2$^{31}$ - 1

4. Solutions

Reuse first row column

m = matrix.size(), n = matrix.front().size()
Time complexity: O(mn)
Space complexity: O(1)

class Solution {
public:
    void setZeroes(vector<vector<int>> &matrix) {
        const int m = matrix.size(), n = matrix.front().size();
        bool first_row_zero = false, first_column_zero = false;
        for (int i = 0; i < m; ++i) {
            first_column_zero |= matrix[i][0];
        }
        for (int i = 0; i < n; ++i) {
            first_row_zero |= matrix[0][i];
        }

        for (int i = 1; i < m; ++i) {
            for (int j = 1; j < n; ++j) {
                if (matrix[i][j] == 0) {
                    matrix[i][0] = matrix[0][j] = 0;
                }
            }
        }

        for (int i = 1; i < m; ++i) {
            for (int j = 1; j < n; ++j) {
                if (matrix[i][0] == 0 || matrix[0][j] == 0) {
                    matrix[i][j] = 0;
                }
            }
        }

        if (first_row_zero) {
            fill(matrix[0].begin(), matrix[0].end(), 0);
        }
        if (first_column_zero) {
            for (int i = 0; i < m; ++i) {
                matrix[i][0] = 0;
            }
        }
    }
};
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