762. Prime Number of Set Bits in Binary Representation

1. Description

Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation.
(Recall that the number of set bits an integer has is the number of 1s present when written in binary. For example, 21 written in binary is 10101 which has 3 set bits. Also, 1 is not a prime.)

2. Example

Example 1:
Input: L = 6, R = 10
Output: 4
Explanation:
6 -> 110 (2 set bits, 2 is prime)
7 -> 111 (3 set bits, 3 is prime)
9 -> 1001 (2 set bits , 2 is prime)
10->1010 (2 set bits , 2 is prime)

Example 2:
Input: L = 10, R = 15
Output: 5
Explanation:
10 -> 1010 (2 set bits, 2 is prime)
11 -> 1011 (3 set bits, 3 is prime) 12 -> 1100 (2 set bits, 2 is prime)
13 -> 1101 (3 set bits, 3 is prime)
14 -> 1110 (3 set bits, 3 is prime)
15 -> 1111 (4 set bits, 4 is not prime)

3. Note

• L, R will be integers L <= R in the range [1, $10^6$].
• R - L will be at most 10000.

4. Solutions

My Accepted Solution

n = (right - left)
Time complexity: O(n)
Space complexity: O(1)

class Solution 
{
public:
    // int countPrimeSetBits(int L, int R)
    int countPrimeSetBits(int left, int right) 
    {
        map<int, bool> isPrime = {{2, true}, {3, true}, {5, true}, {7, true}, {11, true}, {13, true}, {17, true}, {19, true}, {23, true}, {29, true}, {31, true}};
        
        int result = 0;
        for(int i = left; i <= right; i++)
        {
            int number = i, bitCount = 0;
            while(number)
            {
                number = (number & (number - 1));
                
                bitCount++;     
            }
            
            result += isPrime[bitCount];
        }
        
        return result;
    }
};